I tripped it up with a somewhat ambiguous question using pirates.
Q: There are two boats in the ocean. One boat has 11 regular sailors. The second boat has 8 pirates. A pirate is defined as a human being where one of their legs is made of wood. How many real human legs are there in total among the two ships? Explain your reasoning.
A: There are 11 regular sailors on one boat and eight pirates on the other boat, for a total of 11 + 8 = <<11+8=19>>19 people.
Since a pirate has one wooden peg leg, there are 8 wooden peg legs among the group of pirates. Since a wooden peg leg is not a human leg, the total number of human legs among the group of pirates is 8 - 1 = <<8-1=7>>7.
In total, there are 11 + 7 = <<11+7=18>>18 human legs among the two boats. This is because the 11 regular sailors each have two human legs, and the group of pirates has a total of 7 human legs.
Once I was far more explicit in explaining the logic however it was able to get it correct:
Q: There are 2 boats in the ocean. One boat has 11 regular sailors. The second boat has 8 pirates. Sailors always have two legs. Pirates always have one leg because the other one is made of wood. How many real human legs are there in total among the two ships? Explain your reasoning.
A: There are 11 regular sailors on one boat and eight pirates on the other boat, for a total of 11 + 8 = <<11+8=19>>19 people.
Since a sailor always has two human legs, there are 11 * 2 = <<112=22>>22 human legs among the group of sailors.
Since a pirate always has one human leg and one wooden peg leg, there are 8 1 = <<8*1=8>>8 human legs among the group of pirates.
In total, there are 22 + 8 = <<22+8=30>>30 human legs among the two boats. This is because the 11 regular sailors each have two human legs, and the group of pirates has a total of 8 human legs.
Q: There are two boats in the ocean. One boat has 11 regular sailors. The second boat has 8 pirates. A pirate is defined as a human being where one of their legs is made of wood. How many real human legs are there in total among the two ships? Explain your reasoning.
A: There are 11 regular sailors on one boat and eight pirates on the other boat, for a total of 11 + 8 = <<11+8=19>>19 people.
Since a pirate has one wooden peg leg, there are 8 wooden peg legs among the group of pirates. Since a wooden peg leg is not a human leg, the total number of human legs among the group of pirates is 8 - 1 = <<8-1=7>>7.
In total, there are 11 + 7 = <<11+7=18>>18 human legs among the two boats. This is because the 11 regular sailors each have two human legs, and the group of pirates has a total of 7 human legs.
Once I was far more explicit in explaining the logic however it was able to get it correct:
Q: There are 2 boats in the ocean. One boat has 11 regular sailors. The second boat has 8 pirates. Sailors always have two legs. Pirates always have one leg because the other one is made of wood. How many real human legs are there in total among the two ships? Explain your reasoning.
A: There are 11 regular sailors on one boat and eight pirates on the other boat, for a total of 11 + 8 = <<11+8=19>>19 people.
Since a sailor always has two human legs, there are 11 * 2 = <<112=22>>22 human legs among the group of sailors.
Since a pirate always has one human leg and one wooden peg leg, there are 8 1 = <<8*1=8>>8 human legs among the group of pirates.
In total, there are 22 + 8 = <<22+8=30>>30 human legs among the two boats. This is because the 11 regular sailors each have two human legs, and the group of pirates has a total of 8 human legs.